03x^2-6=0

Solution for 03x^2-6=0 equation:

03x^2-6=0

a = 03; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·03·(-6)
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*03}=\frac{0-6\sqrt{2}}{6}
=-\frac{6\sqrt{2}}{6}
=-\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*03}=\frac{0+6\sqrt{2}}{6}
=\frac{6\sqrt{2}}{6}
=\sqrt{2}
$